通过
搜索
搜索juliangut / http-exception
感知HTTP的异常
0.1.1
2018-02-16 15:09 UTC
Requires
- php: ^7.0
- fig/http-message-util: ^1.1
- pascaldevink/shortuuid: ^1.0
Requires (Dev)
- brainmaestro/composer-git-hooks: ^2.1
- editorconfig-checker/editorconfig-checker: ^7.0
- friendsofphp/php-cs-fixer: ^2.0
- infection/infection: ^0.7.0
- phpmd/phpmd: ^2.0
- phpmetrics/phpmetrics: ^2.0
- phpstan/phpstan: ^0.9
- phpstan/phpstan-strict-rules: 0.9
- phpunit/phpunit: ^5.7|^6.0
- povils/phpmnd: ^1.1
- roave/security-advisories: dev-master
- sebastian/phpcpd: ^2.0
- squizlabs/php_codesniffer: ^2.0
This package is auto-updated.
Last update: 2024-09-15 11:17:10 UTC
README
http-exception
感知HTTP的异常
安装
Composer
composer require juliangut/http-exception
用法
需要 composer 自动加载文件
require './vendor/autoload.php';
感知HTTP的异常就像普通的异常一样，但携带一个HTTP状态码
use Jgut\HttpException\HttpException; $exceptionMessage = 'You shall not pass!'; $exceptionDescription = 'You do not have permission'; $exceptionCode = 1001; // Internal code $previousException = new \Exception(); $exception = new BadRequestHttpException($exceptionMessage, $exceptionDescription, $exceptionCode, $previousException); $exception->getStatusCode(); // 400 Bad Request
此外，异常还有一个描述和一个唯一的标识符，可以用于日志记录和显示，例如在API上，允许您在处理错误情况时拥有更多信息
$exception->getDescription(); $exception->getIdentifier();
贡献
发现了bug或有功能请求？请新建一个问题。在新建问题之前，请查看现有的问题。
参见文件CONTRIBUTING.md
许可证
有关许可证条款的副本，请参阅源代码中包含的文件LICENSE