2lenet / credential-bundle
2LE的凭证包。
2.1.2
2024-08-01 13:50 UTC
Requires
- php: ^8.0
- doctrine/doctrine-bundle: ^2.0
- doctrine/orm: ^2.15 || ^3.0
- doctrine/persistence: ^2.0 || ^3.0
- symfony/console: ^6.0 || ^7.0
- symfony/form: ^6.0 || ^7.0
- symfony/framework-bundle: ^6.0 || ^7.0
- symfony/http-kernel: ^6.0 || ^7.0
- symfony/security-bundle: ^6.0 || ^7.0
- symfony/translation: ^6.0 || ^7.0
- symfony/validator: ^6.0 || ^7.0
Requires (Dev)
- ergebnis/phpstan-rules: ^2.1
- phpstan/phpstan: ^1.10
- phpstan/phpstan-deprecation-rules: ^1.1
- phpstan/phpstan-doctrine: ^1.3
- phpstan/phpstan-mockery: ^1.1
- phpstan/phpstan-phpunit: ^1.3
- phpstan/phpstan-strict-rules: ^1.5
- phpstan/phpstan-symfony: ^1.3
- phpunit/phpunit: ^10.3
- slevomat/coding-standard: ^8.13
- squizlabs/php_codesniffer: ^3.7
- dev-master
- 2.1.2
- 2.1.1
- 2.1.0
- 2.0.10
- 2.0.9
- 2.0.8
- 2.0.7
- 2.0.6
- 2.0.5
- 2.0.4
- 2.0.3
- 2.0.2
- 2.0.1
- 2.0.0
- 1.4.2
- 1.4.1
- 1.4.0
- 1.3.2
- 1.3.1
- 1.3.0
- 1.2.1
- 1.2.0
- 1.1.4
- 1.1.3
- 1.1.2
- 1.1.1
- 1.1.0
- 1.0.8
- 1.0.7
- 1.0.6
- 1.0.5
- 1.0.4
- 1.0.3
- 1.0.2
- 1.0.1
- v1.0.0
- dev-fix_scheb_2fa
- dev-sf-7
- dev-improvement/change-block-name
- dev-commandDeleteCredentialCache
- dev-fixLoadCredentials
- dev-dumpCommandWriteJsonOnMultiLines
- dev-fix_visible
- dev-importExportCredentials
- dev-upPhpstan
- dev-fixSymfonyInsightErrors
- dev-fix_publicaccess
- dev-editCredentialEntity
- dev-improvement/cache-sf6
- dev-canVoteOnStatus
- dev-typeEntity
- dev-updateForBeCompatibleSf6
- dev-clearCacheChangeCredential
- dev-repairCheckAllCase
- dev-delete_jquery
- dev-missing_translations
- dev-temp
- dev-style_ergo
This package is auto-updated.
Last update: 2024-09-02 08:06:02 UTC
README
2le的凭证包。
此包提供了一种简单的凭证管理器,用于处理复杂的应用程序。
其目标是简化用户组与角色(凭证)之间的关联。
安装
composer require 2lenet/credential-bundle
flex 应该能完成工作
设置
config/routes/credential.yaml
credential: resource: "@LleCredentialBundle/Resources/config/routes.yaml"
重置分类名称
UPDATE lle_credential_credential SET rubrique= SUBSTRING_INDEX(SUBSTRING_INDEX(role, '_', 2), '_', -1) WHERE role like "ROLE_%";